-(-2b^2+3)-b(2b-3)-3=

Solution for -(-2b^2+3)-b(2b-3)-3= equation:

Simplifying
-1(-2b2 + 3) + -1b(2b + -3) + -3 = 0

Reorder the terms:
-1(3 + -2b2) + -1b(2b + -3) + -3 = 0
(3 * -1 + -2b2 * -1) + -1b(2b + -3) + -3 = 0
(-3 + 2b2) + -1b(2b + -3) + -3 = 0

Reorder the terms:
-3 + 2b2 + -1b(-3 + 2b) + -3 = 0
-3 + 2b2 + (-3 * -1b + 2b * -1b) + -3 = 0
-3 + 2b2 + (3b + -2b2) + -3 = 0

Reorder the terms:
-3 + -3 + 3b + 2b2 + -2b2 = 0

Combine like terms: -3 + -3 = -6
-6 + 3b + 2b2 + -2b2 = 0

Combine like terms: 2b2 + -2b2 = 0
-6 + 3b + 0 = 0
-6 + 3b = 0

Solving
-6 + 3b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 3b = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 3b = 0 + 6
3b = 0 + 6

Combine like terms: 0 + 6 = 6
3b = 6

Divide each side by '3'.
b = 2

Simplifying
b = 2